(w+6)^2=3(w+12)-w^2

Solution for (w+6)^2=3(w+12)-w^2 equation:

(w+6)^2=3(w+12)-w^2

We move all terms to the left:

(w+6)^2-(3(w+12)-w^2)=0


We calculate terms in parentheses: -(3(w+12)-w^2), so:

3(w+12)-w^2

determiningTheFunctionDomain
-w^2+3(w+12)

We add all the numbers together, and all the variables

-1w^2+3(w+12)

We multiply parentheses

-1w^2+3w+36

Back to the equation:

-(-1w^2+3w+36)


We get rid of parentheses

1w^2-3w+(w+6)^2-36=0

We add all the numbers together, and all the variables

w^2-3w+(w+6)^2-36=0

We move all terms containing w to the left, all other terms to the right

w^2-3w+(w+6)^2=36